Random Processes, Autocorrelation and PSD — Summary
Random processes model noise and information signals statistically — the mathematical basis of the Communications section (~10 marks). GATE EC tests stationarity, autocorrelation and power spectral density (1–2 marks).
Key results
- Wide-sense stationary (WSS): mean constant, autocorrelation R_X(τ) depends only on lag τ.
- Autocorrelation R_X(τ) = E[X(t)X(t+τ)]; R_X(0) = average power = E[X²]; R_X(τ) is even, |R_X(τ)| ≤ R_X(0).
- Wiener-Khinchin: PSD S_X(f) = Fourier transform of R_X(τ); total power = ∫S_X(f)df = R_X(0).
- Ergodic: time averages = ensemble averages.
- Output of LTI system: S_Y(f) = |H(f)|²·S_X(f); R_Y = R_X ∗ h ∗ h(−).
- White noise: flat PSD S(f) = N₀/2, R(τ) = (N₀/2)δ(τ) (uncorrelated).
| Quantity | Relation |
|---|---|
| R_X(0) | average power = E[X²] |
| S_X(f) | FT of R_X(τ) (Wiener-Khinchin) |
| LTI output PSD | |
| White noise PSD | N₀/2 (flat) |
Exam Tricks & Tips
- 🎯 R_X(0) equals the total average power — a fast way to get power from autocorrelation.
- 🎯 Wiener-Khinchin: PSD is the Fourier transform of the autocorrelation (and vice versa).
- 🎯 Through an LTI filter H(f), the output PSD is |H(f)|²·S_X(f) — magnitude-squared scaling.
- 🎯 Autocorrelation is even (R(−τ)=R(τ)) and peaks at τ=0.
- 🎯 White noise has a flat PSD N₀/2 and impulse autocorrelation → any two distinct instants are uncorrelated.
- ❌ Common mistake: using H(f) instead of |H(f)|² for the output PSD of an LTI system.
Expected exam pattern
1–2 marks: find average power from R_X(0), PSD via Wiener-Khinchin, output PSD/power through a filter, or test WSS.
Quick recap
WSS: constant mean, R_X(τ) lag-only. R_X(0)=power; S_X(f)=FT{R_X} (Wiener-Khinchin). LTI output S_Y=|H|²S_X. White noise: flat N₀/2, δ-autocorrelation. R_X even, peaks at 0.
Random Processes, Autocorrelation and PSD — Flashcards
Cover the answer, recall, then check. 11 cards on random processes, autocorrelation and PSD for GATE EC.
Q1. Define a wide-sense stationary (WSS) process.
A1. Its mean is constant and its autocorrelation depends only on the time lag τ, not absolute time.
Q2. What does R_X(0) represent?
A2. The average power of the process, E[X²(t)].
Q3. State the Wiener-Khinchin theorem.
A3. The power spectral density S_X(f) is the Fourier transform of the autocorrelation R_X(τ).
Q4. Two key properties of the autocorrelation function?
A4. It is even (R(−τ) = R(τ)) and maximum at τ = 0 (|R(τ)| ≤ R(0)).
Q5. Output PSD of an LTI system with transfer function H(f)?
A5. S_Y(f) = |H(f)|²·S_X(f).
Q6. What is the PSD and autocorrelation of white noise?
A6. Flat PSD S(f) = N₀/2 and autocorrelation R(τ) = (N₀/2)δ(τ).
Q7. Define an ergodic process.
A7. One whose time averages equal its ensemble (statistical) averages.
Q8. How do you get total power from the PSD?
A8. Integrate: P = ∫_{−∞}^{∞} S_X(f) df = R_X(0).
Q9. Why are two distinct samples of white noise uncorrelated?
A9. Its autocorrelation is an impulse at τ = 0, so R(τ) = 0 for any τ ≠ 0.
Q10. Is every WSS process stationary in the strict sense?
A10. Not necessarily — strict-sense stationarity implies WSS, but WSS does not imply strict-sense (except for Gaussian processes).
Q11. Units of power spectral density?
A11. Watts per hertz (W/Hz) — power distributed over frequency.
Random Processes, Autocorrelation and PSD
Real communication signals and noise are random — we can't write them as fixed functions, only describe their statistics. Random-process theory gives the tools: autocorrelation captures how a signal relates to a delayed copy of itself, and its Fourier transform (the power spectral density) shows where the power sits in frequency. GATE tests the Wiener-Khinchin relation and power/PSD calculations.
Core concept: A random process is an ensemble of signals; a wide-sense stationary process is characterised by its mean and autocorrelation R(τ), whose Fourier transform is the power spectral density S(f).
The theory
Beginner — describing randomness
A random process X(t) assigns a random signal to each outcome. Key statistics:
- Mean μ = E[X(t)].
- Autocorrelation R(τ) = E[X(t)·X(t+τ)] — correlation between the process now and τ later.
- Wide-Sense Stationary (WSS): mean is constant and R(τ) depends only on the lag τ (not absolute time).
- Ergodic: time averages equal ensemble averages — lets us estimate statistics from one long record.
Intermediate — autocorrelation and PSD
For a WSS process, the Wiener-Khinchin theorem:
S(f) = FourierTransform{R(τ)} and R(τ) = inverse FT of S(f).
Properties:
- R(0) = E[X²] = average power (also = ∫S(f)df).
- R(τ) is even, and |R(τ)| ≤ R(0) (max at zero lag).
- S(f) ≥ 0 and is even for a real process; its area is the total power.
Advanced — through LTI systems and white noise
- Output of an LTI system with frequency response H(f): the output PSD is S_out(f) = |H(f)|²·S_in(f). Output power = ∫|H(f)|²S_in(f)df.
- White noise: flat PSD S(f) = N0/2 (two-sided) at all frequencies, so R(τ) = (N0/2)δ(τ) — samples at different times are uncorrelated. It has infinite total power (an idealisation), band-limited in practice.
- Cross-correlation and cross-PSD describe two jointly WSS processes; input-output cross-PSD S_xy(f) = H(f)S_x(f) is used in system identification.
Worked example
White noise of PSD N0/2 = 10⁻⁹ W/Hz passes through an ideal low-pass filter of bandwidth B = 10 kHz and gain 1. Find the output noise power.
Output PSD = |H|²·S_in = 1·(N0/2) over ±B (two-sided) → power = (N0/2)·(2B) = N0·B.
Power = 2·(10⁻⁹)·(10⁴) = 2×10⁻⁵ W (20 µW).
Equivalently, using one-sided: N0 = 2×10⁻⁹ W/Hz, power = N0·B = 2×10⁻⁹×10⁴ = 2×10⁻⁵ W. ✔
GATE relevance
1–2 mark NAT/MCQ: autocorrelation ↔ PSD (Wiener-Khinchin), average power from R(0) or ∫S(f)df, output PSD/power through an LTI filter (|H|²S), and white-noise properties. Feeds directly into SNR and probability-of-error problems.
Exam tricks and shortcuts
- Power = R(0) = ∫S(f)df; S(f) = FT of R(τ).
- Through a filter: S_out = |H(f)|²·S_in; integrate for power.
- White noise: S = N0/2 (two-sided), R(τ) = (N0/2)δ(τ), uncorrelated samples.
- Mnemonic: "PSD is the Fourier transform of autocorrelation" (Wiener-Khinchin).
Mixing up one-sided and two-sided PSD by a factor of 2. White noise is often quoted as N0/2 two-sided (defined for −∞ < f < ∞) or N0 one-sided (f ≥ 0 only). Integrate two-sided over ±B or one-sided over 0..B — using the wrong convention doubles or halves the noise power.
- ✓- WSS: constant mean, R(τ) depends only on lag τ.
- ✓- Wiener-Khinchin: S(f) = FT{R(τ)}; R(0) = average power = ∫S(f)df.
- ✓- R(τ) even, |R(τ)| ≤ R(0); S(f) ≥ 0, even.
- ✓- LTI output PSD: S_out(f) = |H(f)|²·S_in(f).
- ✓- White noise: S = N0/2 (two-sided), R(τ) = (N0/2)δ(τ).
- ✓Random signals are described statistically: mean and autocorrelation for a WSS process, with the PSD as the Fourier transform of R(τ) (Wiener-Khinchin). Power is R(0) = ∫S(f)df, filters shape it as |H|²S, and white noise has a flat PSD N0/2 with delta-function autocorrelation.
Random Processes, Autocorrelation and PSD — Formula Sheet
Key formulas
- Autocorrelation: R_X(τ) = E[X(t)X(t+τ)]; R_X(0) = average power.
- Power spectral density: S_X(f) = FT{R_X(τ)} (Wiener–Khinchin).
- WSS process: mean constant, autocorrelation depends only on τ.
- Ergodic: time averages = ensemble averages.
- Power: P = ∫S_X(f)df = R_X(0).
- ✓- R_X(0) = average power.
- ✓- S_X(f) = FT of R_X(τ) (Wiener–Khinchin).
- ✓- WSS: mean constant, R depends only on τ.
The PSD (Fourier transform of autocorrelation) describes how a random signal's power is distributed over frequency.
Random Processes, Autocorrelation and PSD — Worked Example
Worked Example
Problem: A wide-sense-stationary random process X(t) has autocorrelation function R_X(τ) = 5·e^(−2|τ|). Find (a) the average (total) power of the process, and (b) its power spectral density S_X(ω).
Solution:
(a) The average power of a WSS process equals its autocorrelation at zero lag:
P = R_X(0) = 5·e^(0) = 5 W.
(This is E[X²(t)], the mean-square value.)
(b) By the Wiener–Khinchin theorem the PSD is the Fourier transform of the autocorrelation:
S_X(ω) = ∫_(−∞)^(∞) R_X(τ) e^(−jωτ) dτ.
Use the standard transform pair: A·e^(−a|τ|) ↔ 2Aa/(ω² + a²).
Here A = 5 and a = 2, so:
S_X(ω) = (2)(5)(2)/(ω² + 2²) = 20/(ω² + 4).
Check by inverse relation: total power = (1/2π)∫S_X(ω)dω = (1/2π)·(20·π/2) = 5 W ✓ (using ∫dω/(ω²+4) = π/2).
Answer: (a) Average power = 5 W; (b) S_X(ω) = 20/(ω² + 4).
- ✓- For a WSS process the mean-square value (average power) is R_X(0) — no integration needed.
- ✓- Wiener–Khinchin: PSD and autocorrelation are a Fourier transform pair; an exponential R(τ) gives a Lorentzian (1/(ω²+a²)) PSD.
- ✓- The area under the PSD (over all ω, with the 1/2π factor) returns the total power, a handy consistency check.