Energy Bands and Carrier Transport — Summary
Energy bands and carrier transport explain how semiconductors conduct — the physics beneath every diode, BJT and MOSFET. GATE EC tests drift/diffusion, mobility and conductivity (1–2 marks) and it underlies the whole Electronic Devices section (~9 marks).
Key results
- Bandgap E_g: Si ≈ 1.12 eV, Ge ≈ 0.66 eV, GaAs ≈ 1.42 eV (direct). Conductor: overlapping bands; insulator: large gap; semiconductor: moderate gap.
- Drift current: J_drift = q(nμ_n + pμ_p)E; conductivity σ = q(nμ_n + pμ_p).
- Diffusion current: J_diff = qD_n(dn/dx) − qD_p(dp/dx) (electrons diffuse down their gradient).
- Einstein relation: D/μ = kT/q = V_T ≈ 0.026 V at 300 K.
- Mobility falls with temperature (lattice scattering) and heavy doping (impurity scattering).
| Quantity | Expression |
|---|---|
| Conductivity | σ = q(nμ_n + pμ_p) |
| Drift current density | J = σE |
| Einstein relation | D_n/μ_n = D_p/μ_p = kT/q |
| Thermal voltage V_T | kT/q ≈ 26 mV at 300 K |
| Si bandgap | ≈ 1.12 eV |
Exam Tricks & Tips
- 🎯 Einstein relation D/μ = kT/q = V_T ≈ 0.026 V at 300 K links diffusion and mobility — memorise 26 mV.
- 🎯 Drift ∝ E-field; diffusion ∝ concentration gradient. Both electron and hole currents add (same direction for conventional current).
- 🎯 Electron mobility > hole mobility in Si (~1350 vs ~480 cm²/V·s), so n-channel devices are faster.
- 🎯 GaAs is a DIRECT bandgap (good for LEDs/lasers); Si and Ge are INDIRECT (poor light emitters).
- 🎯 Conductivity rises with doping (more carriers) even though mobility drops slightly.
- ❌ Common mistake: forgetting that both carriers contribute to σ = q(nμ_n + pμ_p) — using only majority carriers.
Expected exam pattern
1–2 marks: compute conductivity/resistivity, diffusion coefficient via Einstein relation, or identify direct/indirect bandgap and its consequence.
Quick recap
σ = q(nμ_n+pμ_p); J_drift=σE, J_diff∝gradient. Einstein: D/μ=kT/q=V_T≈26 mV. Si E_g≈1.12 eV; GaAs direct, Si/Ge indirect. Electron mobility > hole mobility.
Energy Bands and Carrier Transport — Flashcards
Cover the answer, recall, then check. 12 cards on energy bands and carrier transport for GATE EC.
Q1. State the conductivity of a semiconductor.
A1. σ = q(n·μ_n + p·μ_p), summing electron and hole contributions.
Q2. State the Einstein relation.
A2. D/μ = kT/q = V_T ≈ 0.026 V (26 mV) at 300 K.
Q3. What drives drift current versus diffusion current?
A3. Drift is driven by the electric field (J = σE); diffusion is driven by the carrier concentration gradient.
Q4. Give the bandgap of Si, Ge, and GaAs.
A4. Si ≈ 1.12 eV, Ge ≈ 0.66 eV, GaAs ≈ 1.42 eV.
Q5. Which of Si, Ge, GaAs has a direct bandgap and why does it matter?
A5. GaAs is direct → efficient light emission (LEDs/lasers); Si and Ge are indirect and are poor emitters.
Q6. How does mobility change with temperature (near room temp)?
A6. It decreases as temperature rises (increased lattice/phonon scattering).
Q7. How does mobility change with doping?
A7. It decreases at high doping due to ionized-impurity scattering.
Q8. Compare electron and hole mobility in silicon.
A8. Electron mobility (1350 cm²/V·s) > hole mobility (480 cm²/V·s), so n-channel devices are faster.
Q9. What is the thermal voltage V_T at 300 K?
A9. kT/q ≈ 25.9 mV ≈ 0.026 V.
Q10. Write the drift current density.
A10. J_drift = q(n·μ_n + p·μ_p)·E = σE.
Q11. Distinguish conductor, insulator, semiconductor by bands.
A11. Conductor: overlapping/partially filled band; insulator: large bandgap; semiconductor: moderate bandgap (~1 eV).
Q12. In which direction do electrons diffuse?
A12. From high to low concentration (down the gradient); the resulting conventional current is opposite to electron flow.
Energy Bands and Carrier Transport
Everything a semiconductor does — conduct, switch, amplify — traces back to how electrons occupy energy bands and how they move when nudged by a field or a concentration gradient. This is the physical bedrock of every device in the syllabus. GATE mines it for carrier-transport calculations (drift, diffusion, mobility) and conceptual band-gap questions.
Core concept: Electrons in a solid occupy allowed energy bands separated by a forbidden gap; conduction needs carriers in the conduction band, and current flows by drift (field-driven) and diffusion (gradient-driven).
The theory
Beginner — the band picture
Isolated-atom levels broaden into bands in a crystal. The valence band (filled) and conduction band (empty at 0 K) are separated by the band gap Eg:
- Insulator: large Eg (>5 eV).
- Semiconductor: moderate Eg (Si ≈ 1.12 eV, Ge ≈ 0.66 eV, GaAs ≈ 1.42 eV at 300 K).
- Conductor: overlapping bands.
Thermal energy promotes electrons across Eg, leaving holes in the valence band; both carry current.
Intermediate — drift and diffusion
Two transport mechanisms:
- Drift: an electric field E exerts force, giving drift velocity vd = μE (μ = mobility). Drift current density Jdrift = q(n·μn + p·μp)·E, so conductivity σ = q(n·μn + p·μp) and resistivity ρ = 1/σ.
- Diffusion: carriers flow down a concentration gradient. Jdiff = qDn·(dn/dx) − qDp·(dp/dx) (signs from carrier charge). Diffusion coefficient D links to mobility by the Einstein relation D/μ = kT/q = VT ≈ 25.85 mV at 300 K.
Advanced — mobility, velocity saturation, recombination
Mobility falls with temperature (lattice scattering, μ ∝ T^(−3/2)) and with doping (impurity scattering). At high fields drift velocity saturates (~10⁷ cm/s in Si) — Ohm's law breaks down. Excess carriers recombine with a characteristic lifetime τ, and diffusion length L = √(Dτ) sets how far minority carriers travel before recombining — a number that governs diode and BJT behaviour. The continuity equation combines drift, diffusion, generation, and recombination into one master transport equation.
Worked example
An n-type Si sample has n = 10¹⁶ cm⁻³, μn = 1350 cm²/V·s. Find its resistivity (ignore holes).
σ = q·n·μn = (1.6×10⁻¹⁹)(10¹⁶)(1350) = 1.6×1350×10⁻³ = 2.16 (Ω·cm)⁻¹.
ρ = 1/σ = 0.463 Ω·cm.
Diffusion coefficient by Einstein: Dn = μn·VT = 1350×0.02585 ≈ 34.9 cm²/s.
GATE relevance
1–2 mark NAT/MCQ: conductivity/resistivity from doping and mobility, Einstein relation (D from μ), diffusion length, band-gap dependence of intrinsic behaviour, and drift-vs-diffusion current. Foundational for PN junction and transistor problems.
Exam tricks and shortcuts
- VT = kT/q ≈ 26 mV at room temperature — the single most-used constant; Einstein D = μ·VT.
- σ = q(nμn + pμp); in strongly doped material one carrier dominates.
- Diffusion length L = √(Dτ); mobility drops as temperature or doping rises.
- Mnemonic: "Drift follows the Field, Diffusion follows the Gradient."
Mixing up mobility μ and diffusion coefficient D, or forgetting they are linked by the Einstein relation D = μ·VT. They are not independent — given one and temperature, the other is fixed. Also, μ decreases with temperature in doped Si (lattice scattering), which surprises many.
- ✓- Semiconductor Eg moderate (Si 1.12 eV); electrons + holes both conduct.
- ✓- Drift: Jdrift = qE(nμn + pμp), σ = q(nμn + pμp), ρ = 1/σ.
- ✓- Diffusion: J ∝ dn/dx; Einstein D/μ = kT/q = VT ≈ 25.85 mV.
- ✓- Diffusion length L = √(Dτ); velocity saturates at high field.
- ✓- μ ∝ T^(−3/2) (lattice), falls with doping.
- ✓Bands and the gap set which materials conduct; carriers move by field-driven drift and gradient-driven diffusion, tied together by the Einstein relation D = μ·VT. Resistivity, diffusion length, and mobility from these relations feed directly into every junction and transistor calculation.
Energy Bands and Carrier Transport — Formula Sheet
Key formulas
- Drift current density: J_drift = q(n μ_n + p μ_p)E; conductivity σ = q(nμ_n + pμ_p).
- Diffusion current: J_n = qD_n(dn/dx); J_p = −qD_p(dp/dx).
- Einstein relation: D/μ = kT/q = V_T ≈ 26 mV at 300 K.
- Resistivity: ρ = 1/σ.
- Mobility μ decreases with temperature and doping (scattering).
- ✓- σ = q(nμ_n + pμ_p).
- ✓- Diffusion J = ±qD(dn/dx); Einstein D/μ = kT/q.
- ✓- V_T = kT/q ≈ 26 mV at room temperature.
Current flows by drift (field-driven) and diffusion (gradient-driven); the Einstein relation links the two coefficients.
Energy Bands and Carrier Transport — Worked Example
Worked Example
Problem: A silicon sample is uniformly doped n-type with donor concentration N_d = 10¹⁶ cm⁻³. The electron mobility is μₙ = 1350 cm²/(V·s). Assuming complete ionization, find the conductivity and the resistivity of the sample. (q = 1.6 × 10⁻¹⁹ C.)
Solution:
With complete ionization and an n-type sample far above intrinsic level, the free electron concentration equals the donor concentration:
n ≈ N_d = 10¹⁶ cm⁻³.
Hole conduction is negligible here (n ≫ p), so drift is dominated by electrons.
Conductivity (electron drift):
σ = q·n·μₙ
σ = (1.6 × 10⁻¹⁹ C)(10¹⁶ cm⁻³)(1350 cm²/V·s)
σ = 1.6 × 10⁻¹⁹ × 1.35 × 10¹⁹
σ = 1.6 × 1.35 = 2.16 (Ω·cm)⁻¹.
Resistivity is the reciprocal:
ρ = 1/σ = 1/2.16 ≈ 0.463 Ω·cm.
Answer: σ ≈ 2.16 (Ω·cm)⁻¹ and ρ ≈ 0.46 Ω·cm.
- ✓- Drift conductivity is σ = q(n·μₙ + p·μₚ); in a strongly doped sample the majority carrier term dominates.
- ✓- Under complete ionization the majority-carrier concentration equals the dopant concentration.
- ✓- Resistivity is simply 1/σ — heavier doping raises carrier density and lowers resistivity.