Measurement of Length, Mass and Time — Summary
This topic supplies the "big and small" numbers boards love in 1-mark fill-in and MCQ items — parallax for stars, light year, parsec, atomic mass unit. It also grounds the order-of-magnitude estimation skill tested in reasoning questions.
Why it matters
No single instrument spans all scales (10⁻¹⁵ m nucleus to 10²⁶ m observable universe). Physicists use direct methods (metre scale, vernier, screw gauge) for ordinary sizes and indirect methods (parallax, echo/RADAR, spectroscopy) for the very large and very small.
Measuring large distances — parallax
View a distant object against a far background from two points a basis b apart; the object shifts by angle θ (the parallax). Then distance D = b / θ (θ in radians). Used to find the distance of the Moon and nearby stars.
Key units and standards
| Quantity | Special unit | Value in SI |
|---|---|---|
| Length (astronomy) | 1 light year | 9.46 × 10¹⁵ m |
| Length (astronomy) | 1 parsec | 3.08 × 10¹⁶ m |
| Length (astronomy) | 1 AU | 1.496 × 10¹¹ m |
| Length (atomic) | 1 angstrom (Å) | 10⁻¹⁰ m |
| Length (nuclear) | 1 fermi | 10⁻¹⁵ m |
| Mass (atomic) | 1 u (amu) | 1.66 × 10⁻²⁷ kg |
Time is now kept by the caesium atomic clock: 1 second = 9,192,631,770 vibrations of the caesium-133 atom. Ordinary masses → common balance; charged particles → mass spectrograph.
Exam Tricks & Tips
- 🎯 Parsec > light year > AU in size — remember 1 parsec ≈ 3.26 light years.
- 🎯 In D = b/θ, θ must be in radians; convert from arc-second/degree first (1° = π/180 rad).
- 🎯 Light year and parsec are units of distance, not time — a favourite trap MCQ.
- 🎯 Angstrom (10⁻¹⁰ m) for atoms, fermi (10⁻¹⁵ m) for nuclei — don't swap them.
- 🎯 For nearby-star parallax the basis is the diameter of Earth's orbit (2 AU), taken 6 months apart.
- ❌ Common mistake: using θ in degrees in the parallax formula — gives an answer ~57× too small.
Expected exam pattern
1-mark: define parsec/light year/amu, or state the caesium-clock definition of the second. 2–3 mark numerical: parallax distance of Moon/star, or convert between Å, nm and m.
Quick recap
Direct vs indirect measurement across scales. Parallax: D = b/θ (θ in rad). Know light year, parsec, AU, angstrom, fermi, amu and the caesium definition of the second.
Measurement of Length, Mass and Time — Flashcards
Cover the answer, recall, then check. 11 cards on measuring length, mass and time.
Q1. State the parallax formula for distance.
A1. D = b/θ, where b is the basis (separation of observation points) and θ is the parallax angle in radians.
Q2. Must the parallax angle be in degrees or radians?
A2. Radians — always convert first.
Q3. How is one second defined using the caesium clock?
A3. The time for 9,192,631,770 vibrations of the caesium-133 atom.
Q4. What is 1 light year in metres?
A4. 9.46 × 10¹⁵ m — the distance light travels in one year.
Q5. What is 1 parsec and how does it compare to a light year?
A5. 3.08 × 10¹⁶ m ≈ 3.26 light years.
Q6. What is 1 astronomical unit (AU)?
A6. The mean Earth–Sun distance, 1.496 × 10¹¹ m.
Q7. Define the angstrom and the fermi.
A7. 1 Å = 10⁻¹⁰ m (atomic sizes); 1 fermi = 10⁻¹⁵ m (nuclear sizes).
Q8. What is 1 unified atomic mass unit (u) in kg?
A8. 1 u = 1.66 × 10⁻²⁷ kg (1/12 the mass of a carbon-12 atom).
Q9. Which instrument measures the mass of charged particles?
A9. The mass spectrograph.
Q10. For measuring a nearby star's distance, what basis is used?
A10. The diameter of Earth's orbit (2 AU), observations taken 6 months apart.
Q11. Name one indirect method to measure large distances.
A11. Parallax (or RADAR/echo methods).
Measurement of Length, Mass and Time
From the size of an atom to the distance of a galaxy, physics spans some 41 orders of magnitude — and one toolkit of clever methods measures it all.
Definition / core idea
Measurement assigns a number and unit to a quantity by comparing it with a standard. Different ranges need different techniques: direct instruments for the human scale, indirect (parallax, echo, decay) methods for the very large or very small.
Deep explanation
Beginner — direct length measurement
- Metre scale: 1 mm resolution.
- Vernier callipers: least count = 1 main-scale division − 1 vernier division, typically 0.1 mm = 0.01 cm.
- Screw gauge (micrometer): least count = pitch / number of circular divisions, typically 0.01 mm.
Reading = main-scale reading + (coincident division × least count).
Intermediate — large distances by parallax
To measure the distance D of a far object, view it from two points a basis b apart; it shifts by angle θ (parallax). Then
D = b / θ (θ in radians).
The astronomical unit and star distances use Earth's orbit as the basis.
Advanced — very small and very large
- Size of a molecule: spread a known volume of oleic acid into a thin film; thickness t = Volume/Area gives the molecular diameter (~10⁻⁹ m).
- Distances by echo/RADAR/LASER: send a pulse, measure round-trip time t; distance = c·t/2.
- Time: modern atomic (caesium) clocks are accurate to 1 part in 10¹³ (lose
1 s in 3 lakh years). Time ranges from nuclear (10⁻²⁴ s) to the age of the universe (10¹⁷ s).
Orders of magnitude to remember
Size of nucleus ~10⁻¹⁴ m, atom ~10⁻¹⁰ m, human ~1 m, Earth's radius ~6.4×10⁶ m, distance to Sun ~1.5×10¹¹ m.
Worked example
A screw gauge has pitch 1 mm and 100 divisions on the circular scale. A wire reads main scale 2 mm and 45th circular division coincides.
Least count = 1 mm/100 = 0.01 mm.
Diameter = 2 mm + 45 × 0.01 mm = 2 + 0.45 = 2.45 mm.
Real-world application
Parallax scaled up gives astronomers stellar distances; scaled down, the same geometry lets your two eyes judge how far away a cricket ball is.
Exam tricks & shortcuts
- Least count of screw gauge = pitch ÷ circular divisions. Vernier LC = 1 MSD − 1 VSD.
- For parallax always convert θ to radians (multiply arc-seconds by 4.85×10⁻⁶).
- 1 light year = 9.46×10¹⁵ m; 1 parsec = 3.08×10¹⁶ m; 1 AU = 1.5×10¹¹ m.
Forgetting to add the zero error correction on vernier callipers and screw gauges. A positive zero error is subtracted from the reading; a negative zero error is added.
- ✓- Vernier LC ≈ 0.01 cm; screw gauge LC = pitch/divisions ≈ 0.01 mm.
- ✓- Parallax: D = b/θ, θ in radians.
- ✓- Small sizes via thin-film (oleic acid) method.
- ✓- Atomic clocks define the second to 1 part in 10¹³.
- ✓- 1 ly = 9.46×10¹⁵ m; 1 parsec = 3.08×10¹⁶ m.
- ✓Match the method to the scale — instruments for the human range, parallax and echoes for the cosmic, thin films and decay for the sub-microscopic.
Measurement of Length, Mass and Time — Formula Sheet
Key formulas
- Parallax method (distance of a star): D = b/θ (b = baseline separation, θ = parallax angle in rad, D = distance).
- Angular size: d = D·α (d = actual size, D = distance, α = angular diameter in rad).
- Range of lengths: ~10⁻¹⁴ m (nucleus) to 10²⁶ m (universe).
- Range of masses: ~10⁻³⁰ kg (electron) to 10⁵⁵ kg (universe); 1 u = 1.66 × 10⁻²⁷ kg.
- Range of times: ~10⁻²² s to 10¹⁷ s.
- Reflection/echo (radar, sonar): distance = ½·v·t (v = wave speed, t = round-trip time).
- ✓- Parallax: D = b/θ (θ in radians).
- ✓- Angular size: d = D·α.
- ✓- Echo distance = ½·v·t.
Use the metre scale, vernier callipers (least count 0.1 mm) and screw gauge (least count 0.01 mm) for progressively smaller lengths.
Measurement of Length, Mass and Time — Worked Example
Worked Example
Problem: A screw gauge has a pitch of 1 mm and 100 divisions on its circular scale. While measuring the diameter of a wire, the main scale reads 2 mm and the 47th circular-scale division coincides with the reference line. There is no zero error. Find the diameter of the wire.
Solution:
Step 1 — Find the least count (LC). The least count of a screw gauge is the pitch divided by the number of circular-scale divisions:
LC = pitch / number of divisions = 1 mm / 100 = 0.01 mm.
Step 2 — Read the main scale (MSR):
MSR = 2 mm.
Step 3 — Read the circular scale contribution:
Circular scale reading = coinciding division × LC = 47 × 0.01 mm = 0.47 mm.
Step 4 — Add the two readings (zero error is nil, so no correction):
Diameter = MSR + (circular scale × LC) = 2 mm + 0.47 mm = 2.47 mm.
Step 5 — Express in SI units if required:
2.47 mm = 2.47 × 10⁻³ m.
Answer: The diameter of the wire is 2.47 mm (2.47 × 10⁻³ m).
- ✓- Least count = pitch ÷ number of circular-scale divisions; here 0.01 mm.
- ✓- Total reading = main scale reading + (coinciding division × least count).
- ✓- Always check for and subtract any zero error before reporting the result.