Types of Relations โ revision notes (CBSE Class 12)
In CBSE Class 12, Relations and Functions is worth about 8 marks, and the very first skill tested is classifying a relation. A relation on a set is nothing more than a subset of ordered pairs โ once you internalise the three test properties, these become guaranteed marks.
Core definition
A relation R on set A is a subset of A ร A. If (a, b) โ R we say "a is related to b", written aRb.
Special relations
- Empty relation: R = โ โ no element of A is related to any element. (R โ A ร A, the smallest.)
- Universal relation: R = A ร A โ every element is related to every element. (The largest.)
- Both empty and universal are called trivial relations.
The three test properties
- Reflexive: (a, a) โ R for every a โ A.
- Symmetric: (a, b) โ R โ (b, a) โ R.
- Transitive: (a, b) โ R and (b, c) โ R โ (a, c) โ R.
Example: on A = {1, 2, 3}, R = {(1,2),(2,3)} is NOT transitive โ it has (1,2) and (2,3) but is missing (1,3). Adding (1,3) would fix transitivity.
Exam Tricks & Tips
- ๐ฏ To DISPROVE a property, one counter-example is enough; to PROVE it, argue for all elements.
- ๐ฏ Reflexive needs every (a,a) โ missing even one diagonal pair kills it.
- ๐ฏ "aRb if a โค b" on real numbers: reflexive โ, transitive โ, symmetric โ (2 โค 3 but 3 โฐ 2).
- ๐ฏ "aRb if a divides b": reflexive & transitive, not symmetric (2|6 but 6โค2).
- ๐ฏ Empty relation is symmetric & transitive vacuously, but reflexive only if A = โ .
- โ Common mistake: assuming symmetric + transitive โ reflexive. False โ the empty relation on a non-empty set is a counter-example.
Expected exam pattern
1-mark MCQ ("which property fails?") or a 2โ3 mark proof asking you to check all three properties for a given R.
Quick recap
Relation = subset of A ร A. Learn the three tests cold: reflexive (all diagonals), symmetric (pairs flip), transitive (chains close). Disprove with one counter-example.
Types of Relations โ Flashcards (CBSE Class 12)
Cover the answer, recall, then check. 12 cards on the must-know facts about types of relations.
Q1. What is a relation R on a set A, formally?
A1. Any subset of A ร A. A pair (a,b) โ R means a is related to b.
Q2. Define the empty relation and universal relation.
A2. Empty: R = โ
(nothing related). Universal: R = A ร A (everything related to everything).
Q3. State the reflexive property.
A3. (a, a) โ R for every a โ A โ every element relates to itself.
Q4. State the symmetric property.
A4. If (a, b) โ R then (b, a) โ R.
Q5. State the transitive property.
A5. If (a, b) โ R and (b, c) โ R, then (a, c) โ R.
Q6. Is "a โค b" on โ symmetric? Why?
A6. No. 2 โค 3 but 3 โฐ 2. It is reflexive and transitive though.
Q7. Is "a divides b" on โ symmetric?
A7. No โ 2 divides 6 but 6 does not divide 2. It is reflexive and transitive.
Q8. How do you DISPROVE a property?
A8. Give a single counter-example.
Q9. How many relations are possible on a set with n elements?
A9. 2^(nยฒ), since A ร A has nยฒ pairs and each is in or out.
Q10. Does symmetric + transitive imply reflexive?
A10. No. The empty relation on a non-empty set is symmetric and transitive but not reflexive.
Q11. Is the empty relation transitive?
A11. Yes, vacuously โ there are no pairs to violate the condition.
Q12. On A = {1,2,3}, is R = {(1,1),(2,2)} reflexive?
A12. No โ (3,3) is missing, so reflexivity fails.
Types of Relations
A seating chart, a family tree, the "is taller than" comparison in your class โ every one of these is secretly a relation, a rule that pairs elements of one set with elements of another. Class 12 formalises this everyday idea and then classifies relations by the special properties they satisfy.
Definition: A relation R from set A to set B is any subset of the Cartesian product A ร B. When A = B we call R a relation on A. Writing (a, b) โ R (read "a is related to b") just means the ordered pair sits inside that subset.
From pairs to properties
If A has m elements and B has n elements, A ร B has mn ordered pairs, so the number of possible relations from A to B is 2^(mn) โ every subset is a legal relation. Two extremes anchor the whole topic:
- Empty relation R = ฯ: no element is related to any element. Example on A = {1,2,3}: R = {(a,b) : a โ b = 8}. Since no difference equals 8, R is empty.
- Universal relation R = A ร A: every element is related to every element. Example: R = {(a,b) : |a โ b| โฅ 0} on any set of reals.
Both empty and universal relations are called trivial relations.
The three defining properties (on a set A)
- Reflexive: (a, a) โ R for every a โ A. Each element relates to itself. ("=" and "is parallel to" are reflexive.)
- Symmetric: (a, b) โ R โน (b, a) โ R. Relation reads the same both ways. ("is a sibling of" is symmetric; "is the father of" is not.)
- Transitive: (a, b) โ R and (b, c) โ R โน (a, c) โ R. Relations chain. ("<" is transitive: a < b, b < c โน a < c.)
WHY these three? They are exactly the abstract skeleton of the notion "sameness". A relation that is reflexive, symmetric and transitive is an equivalence relation โ the star of the next lesson โ because it behaves like equality without literally being equality.
Worked example
Question: On A = {1, 2, 3}, let R = {(1,1), (2,2), (3,3), (1,2), (2,1)}. Classify R.
Solution:
Step 1 โ Reflexive? Need (1,1), (2,2), (3,3). All three present โน reflexive. โ
Step 2 โ Symmetric? The only "mixed" pairs are (1,2) and (2,1); both present, and the diagonal pairs are self-symmetric โน symmetric. โ
Step 3 โ Transitive? Check chains: (1,2) & (2,1) โน need (1,1) โ present. (2,1) & (1,2) โน need (2,2) โ present. No chain fails โน transitive. โ
Conclusion: R is reflexive, symmetric and transitive, hence an equivalence relation.
Exam application
Board and JEE questions almost always ask you to test the three properties or to count relations. Two must-know counts on a set with n elements:
- Number of reflexive relations = 2^(nยฒโn).
- Number of symmetric relations = 2^(n(n+1)/2).
Shortcut / mnemonic โ "RST": Reflexive = Row of self-pairs present; Symmetric = Swap survives; Transitive = Two-step trip allowed. Test in the order R โ S โ T and stop at the first failure to save time.
A relation can be symmetric AND transitive yet not reflexive. Students wrongly "prove" reflexivity by claiming (a,b) โ R and (b,a) โ R force (a,a) โ R by transitivity โ this only works if every a already appears in some pair. If some element relates to nothing, reflexivity fails outright.
- โ- A relation on A is any subset of A ร A; there are 2^(nยฒ) of them.
- โ- Empty (ฯ) and universal (A ร A) relations are the trivial extremes.
- โ- Reflexive: every (a,a) present. Symmetric: pairs survive swapping. Transitive: two hops imply one.
- โ- Reflexive + Symmetric + Transitive together = equivalence relation.
- โ- Reflexive-relation count = 2^(nยฒโn); symmetric-relation count = 2^(n(n+1)/2).
- โ- A relation is just a chosen set of ordered pairs โ nothing mystical.
- โ- Master the R-S-T tests; they unlock equivalence relations and functions.
- โ- Always verify each property against the definition, never by intuition.
Types of Relations โ Formula Sheet
Key formulas / definitions
- Relation R on set A: subset of A ร A.
- Reflexive: (a, a) โ R for all a.
- Symmetric: (a, b) โ R โ (b, a) โ R.
- Transitive: (a, b), (b, c) โ R โ (a, c) โ R.
- Empty relation: R = โ ; universal relation: R = A ร A.
- Number of relations on a set of n elements: 2^(nยฒ).
- โ- Reflexive, symmetric, transitive are the three key properties.
- โ- Number of relations on n elements = 2^(nยฒ).
- โ- Equivalence = all three properties hold.
Relations are classified by which of the reflexive, symmetric and transitive properties they satisfy.
Types of Relations โ Worked Example
Worked Example
Problem: On the set of real numbers R, define a relation R by "a R b if and only if a โค b". Determine whether it is reflexive, symmetric, and transitive.
Solution:
Step 1 โ Test reflexivity. A relation is reflexive if a R a for every a. Since a โค a is always true, the relation is reflexive.
Step 2 โ Test symmetry. It is symmetric if a R b implies b R a. Take a = 2, b = 3: 2 โค 3 is true, but 3 โค 2 is false. So the relation is NOT symmetric.
Step 3 โ Test transitivity. It is transitive if a R b and b R c imply a R c. If a โค b and b โค c, then a โค c is always true. So the relation IS transitive.
Step 4 โ Conclude. The relation "โค" is reflexive and transitive but not symmetric (it is in fact a partial-order relation, not an equivalence relation).
Answer: The relation "โค" is reflexive and transitive but not symmetric.
- โ- Reflexive: a R a for all a; Symmetric: a R b โ b R a; Transitive: a R b, b R c โ a R c.
- โ- A single counterexample disproves a property.
- โ- "โค" is a partial order (reflexive, antisymmetric, transitive), not symmetric.